10x^2+120x-1600=0

Solution for 10x^2+120x-1600=0 equation:

10x^2+120x-1600=0

a = 10; b = 120; c = -1600;
Δ = b2-4ac
Δ = 1202-4·10·(-1600)
Δ = 78400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{78400}=280$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-280}{2*10}=\frac{-400}{20}
=-20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+280}{2*10}=\frac{160}{20}
=8
$